Codeforces Round 936 (Div. 2)
B. Maximum Sum
先求最大连续子列,后面最大连续子列多次加到原数组的和中,$max+max2+max3+…+sum$,类似这样
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| #include <bits/stdc++.h> #define int long long using namespace std; const int INF=1e6+5; const int Mod=1e9+7; int n,a[INF],k; void solve() { cin>>n>>k; int sum3=0; for (int i=1;i<=n;i++) { cin>>a[i]; sum3+=a[i]; sum3%=Mod; } int Max=0,sum=0; for (int i=1;i<=n;i++) { sum=max(0ll,sum); sum+=a[i]; Max=max(Max,sum); } for (int i=1;i<=k;i++) { sum3+=Max; Max*=2; Max%=Mod; sum3%=Mod; } cout<<(sum3%Mod+Mod)%Mod<<"\n"; } signed main() { ios::sync_with_stdio(false); int t=0; cin>>t; while (t--) { solve(); } return 0; }
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